93=1/2(0.3)t^2+4t+4

Solution for 93=1/2(0.3)t^2+4t+4 equation:

93=1/2(0.3)t^2+4t+4

We move all terms to the left:

93-(1/2(0.3)t^2+4t+4)=0


Domain of the equation: 2(0.3)t^2+4t+4)!=0

t∈R


We multiply all the terms by the denominator


-(1+93*2(0.3)t^2+4t+4)=0


We calculate terms in parentheses: -(1+93*2(0.3)t^2+4t+4), so:

1+93*2(0.3)t^2+4t+4

determiningTheFunctionDomain
93*2(0.3)t^2+4t+1+4

We add all the numbers together, and all the variables

4t+93*2(0.3)t^2+5

Wy multiply elements

4t+186t+5

We add all the numbers together, and all the variables

190t+5

Back to the equation:

-(190t+5)


We get rid of parentheses

-190t-5=0

We move all terms containing t to the left, all other terms to the right

-190t=5

t=5/-190

t=-1/38